Scan behavior
you're right, this is somewhat weird, however this design allows you to omit passing a scheduler to Scan. It is always run on the source's execution context (scheduler).
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Hello,I'm wondering why the following two do not behave the same:Enumerable.Range(0, 10).Scan(0, (s, v) => s + v);andEnumerable.Range(0, 10).Scan((s, v) => s + v)It would seem that if I wanted it...
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